Question

An aluminium cube of mass 108g, has a volume of 40cm ^3. Calculate the density of aluminium cube
(a) in g/cm^3 > CGS system
(b) in kg/m^3 > SI system

Answer 1

Answer:

The required density of the Aluminium cube is 2.7 g/cm³ (2700 kg/m³)

Explanation:

Given :

mass of the Aluminium cube = 108 g

volume = 40 cm³

To find :

the density of the aluminium cube

Solution :

The density of a substance is its mass per unit volume.

 $\longmapsto \boxed{\sf d=\dfrac{m}{V}}$

The density of Aluminium cube (in g/cm³) :

$\sf d=\dfrac{m}{V} \\\\ \rm d=\dfrac{108 \ g}{40 \ cm^3} \\\\ \rm d=\dfrac{108}{40} \ g/cm^3 \\\\ \rm d=2.7 \: g/cm^3$

The density of Aluminium cube in kg/m³ :

1 g = 10⁻³ kg

1 cm³ = 10⁻⁶ m³

  $\implies \rm d=2.7 \: g/cm^3 \\\\ \implies \rm d=2.7 \times \dfrac{10^{-3} \: kg}{10^{-6} \: m^3} \\\\ \implies \rm d=2.7 \times 10^3 \ kg/m^3 \\\\ \implies \rm d=2700 \ kg/m^3$

Therefore, the density of the Aluminium cube is 2.7 g/cm³ (2700 kg/m³)