An aluminium resistor has a resistance of 43.6 ohm at 20 0C and 50.8 ohm at 60 0C. Determine the temperature coefficient of resistance of aluminium at 0 0C, its resistance at 0 0C and at 40 0C.
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Explanation:
Given: The resistance of a conductor at 20
∘
C is 3.15Ω and at 100
∘
C is 3.75Ω.
To find the temperature co-efficient of resistance of the conductor.
Solution:
Here R
20
=3.15,R
100
=3.75
We know that R
t
=R
0
(1+αt)
where R
0
= resistance at 0
∘
C
and R
t
= resistance at t
∘
C
α= temperature coefficient of resistance
Now,
R
20
=3.15=R
0
(1+20α)....(i)
R
100
=3.75=R
0
(1+100α)....(ii)
Dividing (i) and (ii), we get
R
0
(1+100α)
R
0
(1+20α)
=
3.75
3.15
⟹3.75(1+20α)=3.15(1+100α)
⟹3.75+75α=3.15+315α
⟹240α=0.6
⟹α=0.0025
∘
C
−1
From equation(i) ,
R
0
=
1+20α
3.15
⟹R
0
=
1+20(0.0025)
3.15
⟹R
0
=
1+0.05
3.15
⟹R
0
=3Ω
is the temperature co-efficient of resistance of the conductor.
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