Question

An aluminium rod of length 2 m held fixed in horizontal position from its one end has the other end free When the temperature of rod increases by 100 o C . the thermal strain produced in rod will be ( a = 1.6 × 10 6 / o C )
A Zero
B 0.08
C 0.1
D 0.4

Answer 1

Answer:

Thermal strain in the rod is given as

$\frac{\Delta L}{L} = 1.6 \times 10^{-4}$

Explanation:

As we know that if temperature of the solid rod is increased then due to thermal expansion its length will increase

Here we know that the coefficient of thermal expansion is given as

$\alpha = 1.6 \times 10^{-6}$

Change in temperature of the rod is

$\Delta T = 100$

Now we know that

$\Delta L = L \alpha \Delta T$

Now thermal strain is given as

$\frac{\Delta L}{L} = \alpha \Delta T$

so we have

$\frac{\Delta L}{L} = (1.6 \times 10^{-6})(100)$

$\frac{\Delta L}{L} = 1.6 \times 10^{-4}$

#Learn

Topic : thermal Expansion

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