Question

An aluminium sample has mass 54 gram what is the mass of same number of magnesium atom

Answer 1

No.of Al atoms in 54 g sample =
No.of moles in 54 g Al = 54 ÷ 27= 2 moles
No.of atoms = 2×6.022×10^23
Mass of 1 mol Mg (6.022 ×10^23) =24g
So mass of 2 × 6.022 × 10^23 = 48 g

Answer 2

Answer:

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Mole $= \frac{given \: mass}{molar \: mass}$

Then, moles of aluminum $= \frac{54}{27}$$= 2$

According to question,

For 2 moles of magnesium it's mass is $2 × 24 = 48g$

Hence, the required mass for same number of magnesium atoms is 48g.

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