An aluminium scale (a = 2.4 x 10-5 (Cº)-]
calibrated at 25°C is measuring length of copper rod
[a. = 1.7 x 10-5 (Cº)-] at 125°C. If the reading
shown is 100 m, then the correct reading is
(1) 100.7 m
(2) 100.07 m
(3) 107 m
(4) 170 m
Answers
Answered by
16
answer : option (2) 100.07 m
coefficient of linear expansion of copper, α = 1.7 × 10^-5/°C
coefficient of linear expansion of aluminium, α' = 2.4 × 10^-5/°C
temperature difference, ∆T = (125°C - 25°C) = 100°C
using , L_app = L_al - L_cu
= l(1 + α'∆T) - l(1 + α∆T)
= l(α' - α)∆T
= 100 × (2.4 - 1.7) × 10^-5 × 100
= 10⁴ × 0.7 × 10^-5
= 0.07 m
hence, correct reading is l + L_app = (100 + 0.07)m = 100.07m
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(2) 100.07 m
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