Question

an aluminium vessel of mass 200g contains 0.5l of water. what is the heat required to raise the temperature of this system from 25 degrees Celsius to 75 degrees Celsius

Answer 1

Given - mass of aluminium - 200g

Volume of water - 0.5l

Initial temperature - 25° C

Final temperature - 75° C

Find - Q or heat required to raise the temperature

Answer -

Mass of aluminium in kilogram will be - 0.2kg

Mass of water in kilogram will be - 0.5kg

Specific heat capacity of water is -

4186 J/kgºC

Specific heat capacity of aluminium is - 900 J/kgºC

To calculate the heat required, the formula used will be -

Q = mc∆t

Here, q is heat required, m denotes mass, c is specific heat capacity, ∆t is change in temperature

Heat required for aluminium vessel and water will be calculated seperately and then it will be added.

For aluminium-

Q = 0.2*900* 50

Q = 9000 J or 9 kJ

For water-

Q = 0.5*4186*50

Q = 104650 J or 105kJ

Total Q = 105+9 = 114 kJ

Therefore, total heat required is - 114kJ