Question

An aluminium wire has diameter 0.5 mm and resistivity 2.8×10^-4 ohm-cm. How much length of this wire is required to make a 10 ohm coil?​

Answer 1

Answer:

The formula is Resistance=Rho * Length/Area so that

Length=Resistance * Area/Rho.

Area is Pi/4 times diameter squared, or 0.001963 square cm.

Then length is 10 ohms *.001963 square cm / 2.8E-6 ohm cm or 7012 cm, same as 70.12 meter.

Answer 2

Answer:

d=0.5mm

A=πr²

A = π 0.25 /4

RESISTIVITY = 2.8X10^-4

R=10ohm

R = RESISTIVITY X L / A

R= 2.8 X 10^ -4 * L /π*0.25 /4

10 * π * 0.25 *10⁴/2.8 = L

0.7* 10⁵ =L

7000 CM =L

70 M = L

Explanation:

PLEASE MARK MY ANS AS BRAINLIEST PLEASE