an aluminium wire of cross section 3*10-4 m2 has a length of 51m . if the resistivity of aluminium is 2.6*10-8ohm. m , what would be the resistance of the wire ?
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R=(rho)l/A
R=2.6*10^-8(51)/3*10^-4
R=0.000000026(51)/0.00003
R=0.0442 ohm
R=2.6*10^-8(51)/3*10^-4
R=0.000000026(51)/0.00003
R=0.0442 ohm
when
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