Question

An aluminium wire of diameter 4 mm carries a current of 4.4 A. Then the current density is

Answer 1

Answer:

Explanation:

So here we've an aluminum wire of thickness 4mm

Thus, r=2mm and I=2.2A

Current Density,

J=I/A

A= πr²= π(2x10^{-3})²

J= (2.2/π(2x10^{-3})²)

=1.75x10^{5} A/m²