An aluminium wire of length 2m and diameter 1 mm has resistivity of 2.8 × 10^-6 ohmmeter calculate the resistance
Answers
Answered by
28
Resistance=Resistivity×L/area
r=2.8×10^-6×2/3.14×(0.5×10^-3)²×2
R=2.8/3.14×0.25
R=3.5668 ohm
r=2.8×10^-6×2/3.14×(0.5×10^-3)²×2
R=2.8/3.14×0.25
R=3.5668 ohm
Answered by
22
Answer:
Resistance=Resistivity×L/area
r=2.8×10^-6×2/3.14×(0.5×10^-3)²×2
R=2.8/3.14×0.25
R=3.5668 ohm
Explanation:
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