an aluminium wire of resistance R is pulled so that its length becomes four times its original length find its new resistance
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HEYA MATE,
HERE IS UR ANSWER.
Thanks for asking this question.
Given that ,
Resistance of wire = R ohm
let the length of wire be l
We know that,
R is directly proportional to the length of conductor.
Therefore,
The resistance also becomes 4 times its original resistance and its area becomes 1/4 of its original cross sectional area.
Hence, Resistance of wire is 4l/1×A/4=16l/A
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
Given that ,
Resistance of wire = R ohm
let the length of wire be l
We know that,
R is directly proportional to the length of conductor.
Therefore,
The resistance also becomes 4 times its original resistance and its area becomes 1/4 of its original cross sectional area.
Hence, Resistance of wire is 4l/1×A/4=16l/A
I HOPE IT HELPS U.
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0
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