Question

An aluminum nail has an excess charge of +3.2 microC. Then the number of electrons that must be added to

the nail to make it electrically neutral is :​

Answer 1

Answer:

2 × 10^13 electrons

Explanation:

Excess charge in nail = 3.2 × 10^-6 C

Let charge required to make it electrically neutral = x

3.2 × 10^-6 + x = 0

So, x = - 3.2 × 10^-6 C

Using the concept of quantisation of charge,

q=ne

where q is the magnitude of charge, e is charge of electron and n is number of electrons.

- 3.2 × 10^-6 = n × (- 1.6 × 10^-19)

n = 2 × 10^13

So, Number of electrons to be added to the nail to make it electrically neutral = 2 × 10^13

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