An aluminum of length 30m is made into a cone for the temperature range. Find the change in length of the Al sheet.
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Answer:
We know that change in length ΔL=LαΔT
ΔT=40−20=20 , L=5m
ΔL=5×α×20
ΔL=5×1.2×10
−5
×20
=1.2×10
−3
=1.2mm
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