An aluminum sphere is 8.75 cm in diameter. What will be its %change in volume if it is heated from 30°C to 160°C?
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Answer:
☞ r = 8.75/2
☞ 30 C → 160C T = 13o
☞ V = Bv angle T ☞ B =75*10 power-6 C
☞ V = 4 π (8.75/2)cm whole power 3
☞ 350.8 cm power3
☞ %V = V1/V2
☞ 3.42/350.8
☞ 0.98% answer
Explanation:
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