Physics, asked by ishita8112005, 1 year ago

An ammeter has 10 divisions 0 A and 1 A. What is its least count?

Answers

Answered by pallavisrinivas2004
13

Answer:

Two given marks of the voltmeter = 0 and 1v

Potential difference = 1-0 = 1V

No. of divisions between these two marks = 10

Least count = 1/10 = 0.1 volts

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