An ammeter has 20 divisions between 0 to 2 on its scale . Find its least count of the ammeter
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Answered by
316
Two given marks of the voltmeter = 0 and 2 V
Potential difference = 2-0 = 2V
No. of divisions between these two marks = 20
Least count = 2/20 = 0.1 volts
Potential difference = 2-0 = 2V
No. of divisions between these two marks = 20
Least count = 2/20 = 0.1 volts
Answered by
29
Answer:
0.1 is the answer............
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