Question

An ammeter is connected in series with an unknown resistance, and a voltmeter is connected across the terminals of the resistance. If the ammeter reads 1.2 A and the voltmeter reads 18 V, what is the amount of charge passing through the medium? (For this, it is not given straight out, but you may assume a time of 1 second.)

Answer 1

Answer:

yes

Explanation:

An ammeter is connected in series with an unknown resistance, and a voltmeter is connected across the terminals of the resistance. If the ammeter reads 1.2 A and the voltmeter reads 18 V, what is the amount of charge passing through the medium? (For this, it is not given straight out, but you may assume a time of 1 second.)

Answer 2

Given:

An ammeter is connected in series with an unknown resistance, and a voltmeter is connected across the terminals of the resistance. If the ammeter reads 1.2 A and the voltmeter reads 18 V.

To find:

• Value of resistance

• Charge flowing through the resistance in one second.

Calculation:

Reading of ammeter is the current passing through the circuit = 1.2 A

Reading of voltmeter is your potential drop across the resistor = 18 V

So , Applying Ohm's Law:

$\therefore \: V = I \times R$

$= > 18 = 1.2\times R$

$= > R = \dfrac{18}{1.2}$

$\boxed{ = > R = 15 \: ohm}$

Now , current is defined as the instantaneous rate of flow of charge.

$\therefore \: I = \dfrac{q}{t}$

$= > q = I \times t$

$= > q = 1.2 \times 1$

$\boxed{ = > q = 1.2 \: coulombs}$

Hope It Helps.