Question

An ammeter of resistance 0.8 ohm can measure currents upto 1A. What must be the shunt resistance to measure current upto 5A.​

Answer 1

We have,

resistance of ammeter, RA=0.80 ohm and maximum current across ammeter, IA=1.0A.

So, voltage across ammeter,

V=IR=1.0×0.80=0.8V.

Let the value of shunt be x .

(i) Resistance of ammeter, with shunt,

R=RAxRA+x=0.8x0.8+x

Current through ammeter, I=5A

∴(0.8x0.8+x)×5=0.8⇒0.8x×5=0.8(0.8+x)

4x=0.64+0.8x

x=0.643.2=0.20Ω

Thus, the shunt resistance is 0.20Ω.

(ii) Combined resistance of the ammeter and the shunt,

R=0.8x0.8+x=0.8×0.20.8+0.2=0.161=0.16Ω.

Hope it helps!!

Thank you ✌️

Answer 2

Answer:

The shunt resistance is 0.2Ω

Explanation:

Shunt resistance= product of Current through galvanometer and Galvanometer resistance divided by remaining current through shunt resistance.

Shunt resistance= 1 * 0.8/ 5-1

= 0.8/4

= 0.2Ω.

Hope it helps..

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