Question

An ammeter with a resistance of 5.0 ohm is connected in series with a 3.0 V cell and and a lamp rated at 300 mA , 3V. calculate the current that the ammeter will measure.
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Answer 1

Answer:

0.2 A

Explanation:

Resistance of Lamp :-

V=IR

3V = 0.3 • R

R = 3/0.3

R1 = 10 ohm

Equivalent resistance in series :-

Rs = Ra(Ammeter Resistance) + R1

Rs = 5 + 10

Rs = 15 ohm

Ammeter Reading

V=IR

3V=I • 15ohn

I = 3/15

I = 1/5

I = 0.2 A

Ammeter reading is 0.2A

Answer 2

Explanation:

the ammetere has a resistance 5 ohm and it is connected in series so for the lamp I=300mA=300/1000=0.3A and V=3v so

Resistance of lamp=V/i=3/0.3=10 ohm

Now total voltage =3v and resistance is in series

R=R1+R2=5+10=15 ohm

Now on series current is same so ammeter and lamp will have same current flowing which is

i=V/R=3/15=1/5=0.2A

Thus current flowing in ammeter is 0.2A