Math, asked by 223032t, 11 months ago

An amount of $180 is shared among three people in the ratio x:y:z. Find the smallest and largest share, given that x=4, y=11 and z=3.
answer with explanation please.

Answers

Answered by Anonymous
4

Answer:

Let the amount of money that is divided be C.

It is divided in the ratio 10 : 7 : 5 among X, Y, Z.

This can be written in another way as X gets 10/ 22 of the amount, Y gets 7/22 of the amount and Z gets 5/22 of the amount.

As Y gets $14 more than Z

(7/22)*C - (5/22)*C = 14

=> C*( 2/ 22) = 14

=> C = 14*11

=> C = 154

The amount that X gets is (10/ 22)*154 = 70

The required value for the total amount is $154 and X gets $70

Answered by rakeshmohan73
3

Total Amount to be shared

= 180$

The ratio given is 4,11,3 for x,y,z respectively.

Adding Ratios to calcute each share ⇒ 4+11+3

=18

Calculating each share:

for x ⇒ 180×4÷18

=40$

for y⇒ 180×11÷18

=110$

for z⇒ 180×3÷18

=30$

Therefore we get,

Largest Share as 110$ for y

Smallest Share as 30$ for z.

#SPJ2

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