An amount of $180 is shared among three people in the ratio x:y:z. Find the smallest and largest share, given that x=4, y=11 and z=3.
answer with explanation please.
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Answered by
4
Answer:
Let the amount of money that is divided be C.
It is divided in the ratio 10 : 7 : 5 among X, Y, Z.
This can be written in another way as X gets 10/ 22 of the amount, Y gets 7/22 of the amount and Z gets 5/22 of the amount.
As Y gets $14 more than Z
(7/22)*C - (5/22)*C = 14
=> C*( 2/ 22) = 14
=> C = 14*11
=> C = 154
The amount that X gets is (10/ 22)*154 = 70
The required value for the total amount is $154 and X gets $70
Answered by
3
Total Amount to be shared
= 180$
The ratio given is 4,11,3 for x,y,z respectively.
Adding Ratios to calcute each share ⇒ 4+11+3
=18
Calculating each share:
for x ⇒ 180×4÷18
=40$
for y⇒ 180×11÷18
=110$
for z⇒ 180×3÷18
=30$
Therefore we get,
Largest Share as 110$ for y
Smallest Share as 30$ for z.
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