Physics, asked by prawinkrishna213, 10 months ago

An amount of 250 joules of work is done in transferring 20 coulombs of charge from one terminal of a battery to another. What is the potential difference between the two terminals of a battery?

Answers

Answered by Cake21
3

Answer:

Explanation:

Work done(w)=250 j

Charge(q)=20c

Potential difference (v)=w/q

=250/20

=25/2=12.5 volts

HOPE THIS HELPS YOU

Answered by pmvjs299
5

Answer:

Potential difference = 12.5 V

Explanation:

work done = 250 J

charge = 20 C

now,

potential difference = work done / charge

                                 = 250 / 20

                                 = 12.5 volts

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