An amount of 250 joules of work is done in transferring 20 coulombs of charge from one terminal of a battery to another. What is the potential difference between the two terminals of a battery?
Answers
Answered by
3
Answer:
Explanation:
Work done(w)=250 j
Charge(q)=20c
Potential difference (v)=w/q
=250/20
=25/2=12.5 volts
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Answered by
5
Answer:
Potential difference = 12.5 V
Explanation:
work done = 250 J
charge = 20 C
now,
potential difference = work done / charge
= 250 / 20
= 12.5 volts
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