An amount of 3240 has to be returned for a principal of 2560 borrowed at interest of 2.5percentag annum compounded annually find the time period after which this amount is returned
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Step-by-step explanation:
A=3240
P=2560
r=2.5pa compounded annually
a= p(1+r/100)^n
3240=2560(1+2.5/100)^n
3240/2560=(1.025)^n
81/64=(1.025)^n
√81/64=1.025
9/8=1.025
x= 1.025*8/9
x=.091
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