Question

An amount of ₹68 is divided into two parts such that seventh part of first is equal to tenth part of the second. What is the first part

Answer 1

may be it satisfy you

Answer 2

The first part of the amount = ₹ 28

Given :

An amount of ₹68 is divided into two parts such that seventh part of first is equal to tenth part of the second.

To find :

The first part

Solution :

Step 1 of 2 :

Form the equation

Let the amount of ₹68 is divided into two parts such that first part = ₹ p and second part = ₹ (68 - p)

By the given condition

$\displaystyle \sf{ \frac{1}{7} \times p = \frac{1}{10} (68 - p) }$

Step 2 of 2 :

Find first part of the amount

$\displaystyle \sf{\frac{1}{7} \times p = \frac{1}{10} (68 - p) }$

$\displaystyle \sf{ \implies 10 \times p = 7 \times (68 - p)}$

$\displaystyle \sf{ \implies 10p = 476 - 7p}$

$\displaystyle \sf{ \implies 10p +7p = 476 }$

$\displaystyle \sf{ \implies 17p = 476 }$

$\displaystyle \sf{ \implies p = \frac{476}{17} }$

$\displaystyle \sf{ \implies p = 28 }$

So we get ,

First part = ₹ p = ₹ 28

Second part = ₹ (68 - p) = ₹ (68 - 28) = ₹ 40

Hence first part of the amount = ₹ 28

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