An amount of money double itself in 10 years. what is the rate of interest ?
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Let R be the interest rate.
Let 100 be the Principal P.
100(1+ R÷100) ^10 = 200
{(100+R)÷100}^10 =2
(100+R)/100= 2^(1/10)
(100 + R)/100 = 1.07177346253629
100 + R =107.177346253629
R = 7.177346253629
Why not put similar cases in a general formula?
At what rate R will an amount become “n”times, when the period is N years?
Just solve the formula:
R = {100 × n^(1/N)} - 100
I.e. 100 x Nth root of number of times less 100
Let 100 be the Principal P.
100(1+ R÷100) ^10 = 200
{(100+R)÷100}^10 =2
(100+R)/100= 2^(1/10)
(100 + R)/100 = 1.07177346253629
100 + R =107.177346253629
R = 7.177346253629
Why not put similar cases in a general formula?
At what rate R will an amount become “n”times, when the period is N years?
Just solve the formula:
R = {100 × n^(1/N)} - 100
I.e. 100 x Nth root of number of times less 100
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Hello hi your answer
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