Math, asked by michelledp03, 7 months ago

An amount of Rs. 6600 is divided among three partners X, Y and Z, so that X receives
3/7th of what Y and Z received together and Y receives 13/20th of what X and Z received
together. Find the share of each partner.
72/7​

Answers

Answered by trishusui200
0

Answer:

X=1980, Y = 2600, Z= 2020

Step-by-step explanation:

X + Y + Z = 6600..............(1)

X = 3/7(Y + Z)

Y + Z = 7X/3...............(2)

again

Y = 13/20(X + Z)

X + Z = 20Y/13..............(3)

from (1) and (2)

X + 7X/3 = 6600

(3X+7X)/3 = 6600

10X/3 = 6600

X = 6600*3/10

X = 1980

from (1) and (3)

Y + 20Y/13 = 6600

33Y/13 = 6600

Y = 6600*13/33

Y = 2600

putting value of X and Y in (1)

1980+2600+Z = 6600

Z = 6600 - 4580

Z = 2020

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