Question

An amount of Rs 950 is distributed among A,B&C in the ratio 5:11:3.What is the difference between the share of B&A

Answer 1

Answer:

Rs. 300

Step-by-step explanation:

let the ratios of A, B and C is 5x, 11x and 3x

ATQ 5x + 11x + 3x =950

19x = 950

x = 50

Difference between share of A and B is 11x - 5x = 6x

and 6x = 6 x 50 = 300

Answer 2

★ How to do :-

Here, we are given with the total amount that should be distributed between three people belt A, B and C. We are also given with the ratio of the distribution of the amount to each of them. But, we aren't given with the accurate amount that is distributed to each. We use some other concepts to solve this problem which are very useful in these type of sums. This property is known as transition of numbers and variables from one hand side to the other. While using this property the sign of the particular number or the variable changes. So, let's solve!!

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➤ Solution :-

${\tt \leadsto 5 : 11 : 3 = 950}$

Insert a variable x to all the part of ratios.

${\tt \leadsto 5x + 11x + 3x = 950}$

Add all the values having same variables.

${\tt \leadsto 19x = 950}$

Shift the value 19 from LHS to RHS.

${\tt \leadsto x = \dfrac{950}{19}}$

Simplify the fraction to get the value of x.

${\tt \leadsto x = 50}$

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Now, multiply the value of x to all the part of ratios.

Amount given to A :-

${\tt \leadsto 5x = 5 \times 50}$

Multiply the numbers.

${\tt \leadsto Rs \: \: 250}$

Amount given to B :-

${\tt \leadsto 11x = 11 \times 50}$

Multiply the numbers.

${\tt \leadsto Rs \: \: 550}$

Amount given to C :-

${\tt \leadsto 3x = 3 \times 50}$

Multiply the numbers.

${\tt \leadsto Rs \: \: 150}$

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Now, let's find the difference between the shares of B and A.

Difference between B and A :-

${\tt \leadsto 550 - 250}$

Subtract the values to get the answer.

${\tt \leadsto Rs \: \: 300}$

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${\red{\underline{\boxed{\bf So, \: the \: difference \: between \: B \: and \: A \: is \: 300.}}}}$