An amount of rupees 7600 is divided among P, Q, R much that if then share is reduced by rupees 42,147 and 211 respectively the the remainder shall be in the ratio 3:4:5. What will be the R's share
Answers
Step-by-step explanation:
Total amount distributed among P, Q & R =Rs4830.
Total amount diminished =Rs(5+10+15)=Rs30.
So the rest of the amount =Rs(4830−30)=Rs4800.
To get The individual's share we divide Rs 4800 in the ratio
3:4:5.
So P's amount
=Rs
3+4+5
3
×4800=Rs
12
3
×4800=Rs1200.
∴ P's share before deduction of Rs 5
=Rs(1200+5)=Rs1205.
- R's share is equal to Rs.3211 .
Given :-
- Total amount divided among P, Q and R = Rs.7600 .
- Each share is reduced by rupees 42, 147 and 211 respectively .
- Ratio of remainder = 3 : 4 : 5
To Find :-
- What will be the R's share ?
Solution :-
We have given that, ratio of remaining share after amount is reduced is equal to 3 : 4 : 5 .
So, Let us assume that, the the remaining share of P, Q and R is equal to Rs. 3x , Rs. 4x and Rs. 5x respectively . { As 3x : 4x : 5x = 3 : 4 : 5 . }
then,
→ Reduced share of P = Rs. 3x
→ Reduced amount = Rs. 42
So,
→ Initial share of P = Reduced share + Reduced amount = Rs. (3x + 42)
similarly,
→ Reduced share of Q = Rs. 4x
→ Reduced amount = Rs. 147
So,
→ Initial share of Q = Reduced share + Reduced amount = Rs. (4x + 147)
and,
→ Reduced share of R = Rs. 5x
→ Reduced amount = Rs. 211
So,
→ Initial share of R = Reduced share + Reduced amount = Rs. (5x + 211)
now, we have given that, total amount divided among P, Q and R was Rs. 7600 .
therefore,
→ Initial share of P + Initial share of Q + Initial share of R = Rs. 7600
→ (3x + 42) + (4x + 147) + (5x + 211) = 7600
→ 3x + 4x + 5x + 42 + 147 + 211 = 7600
→ 12x + 400 = 7600
→ 12x = 7600 - 400
→ 12x = 7200
→ 12x = 12 × 600
dividing both sides by 12,
→ x = Rs. 600
hence,
→ Initial share of R = Rs. (5x + 211)
putting value of x now,
→ Initial share of R = 5 × 600 + 211
→ Initial share of R = 3000 + 211
→ Initial share of R = Rs. 3211 (Ans.)
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