Question

an amount of water of mass 20g at 0c is mixed with 40g of water at 10c final temperature of the mixture is. a.-20c b.6. 67c. c.5c d.0c

Answer 1

b 6.67°c will be final temp. of the mixture

Answer 2

Given :

Mass of water having 0°C temperature (m₁) = 20 g

Mass of water having 10°C temperature (m₂) = 40 g

To Find :

Final temperature of the mixture

Solution :

The final temperature of the mixture when an amount of water of mass 20g at 0°C is mixed with 40g of water at 10°C

Final Temperature (T) = $\frac{m_1T_1 + m_1T_2}{m_1 + m_2}$

Here, m₁ = 20 g; m₂ = 40 g; T₁ = 0° C; T₂ = 10° C

Final Temperature (T) = $\frac{m_1T_1 + m_1T_2}{m_1 + m_2}$

                                    = $\frac{20*0 + 40*10}{20 + 40}$

                                    = $\frac{400}{60}$

                                    = 6.67° C

Therefore, the final temperature of the mixture is 6.67° C.

The correct option is (b) 6.67°C