an amplifier has I/P of 1000 volts and gain of th amplifier is 20.50% of the total output if fed to the I/P as feedback.Find the value of final O/P and also find whether the amplifier will be able to get sustained oscillations or not?
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here is ua answer...
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The Gain for the filter is given as -
A=100A=100
With negative feedback, the filter Gain will reduce to AfAf
Af=A1+ABAf=A1+AB
For a 5% feedback, B=120B=120, so
Af=1001+100/20=1006Af=1001+100/20=1006
This the new Gain of the system. With reduction in the Gain, the bandwidth will be increased in proportion -
BWnew=AAfBWoldBWnew=AAfBWold
BWnew=100∗6100200BWnew=100∗6100200 kHz
BWnew=1200BWnew=1200 kHz .
hope it help u
...................
The Gain for the filter is given as -
A=100A=100
With negative feedback, the filter Gain will reduce to AfAf
Af=A1+ABAf=A1+AB
For a 5% feedback, B=120B=120, so
Af=1001+100/20=1006Af=1001+100/20=1006
This the new Gain of the system. With reduction in the Gain, the bandwidth will be increased in proportion -
BWnew=AAfBWoldBWnew=AAfBWold
BWnew=100∗6100200BWnew=100∗6100200 kHz
BWnew=1200BWnew=1200 kHz .
hope it help u
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