Math, asked by riyagupta95, 7 months ago

An analogue clock is set right at 5 AM The clock gains 20 seconds in 3 minutes, on the same day, what is the true time when the clock reads 5 PM.


Answers

Answered by amitnrw
6

Given :  An analogue clock is set right at 5 AM The clock gains 20 seconds in 3 minutes,  

To Find : on the same day, what is the true time when the clock reads 5 PM.

Solution:

An analogue clock is set right at 5 AM

The clock gains 20 seconds in 3 minutes

=> Clock shows time 3 minutes 20 secs  when time actual has been 3 minutes

Clock shows 3 minutes 20 secs = 3 * 60 + 20  = 200 Sec

While actual time = 3 minutes = 180 sec

Every 200 Secs  of clock time actual time = 180 sec

For every  1 sec of clock time  actual time = 180/200  =  9/10 Sec

Hence actual time is  ( 9/10) of clock time

Clock reads 5PM after clock 12 hrs

Hence actual time had been  = (9/10) 12   hrs

or time left for 5PM  =  (1/10) 12  hrs  

= 1.2 hrs = 1 hr  12   minutes

so actual times  1 hr  12   minutes  before 5 PM =   12 minutes before 4 PM

= 3 hr 48  Minutes  PM

true time when the clock reads 5 PM.  =  3 hr 48  Minutes   PM

3 : 48 PM

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Answered by rishispandan2006
0

Answer:

 seconds gain in 3 minutes. So when actual time is 3 minutes the fast clock shows 3 minutes 20 seconds ie when it is 3*60=180 seconds the fast clock shows 200 seconds. Difference 180/200 or 9/10

5 am to 5 pm =12 hours

When the fast clock covers 12 hours and shows 5 p.m., the true clock will show 720×9/10=648 minutes . Difference 720-648 =72 minutes or 1 hour 12 minutes behind

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