Question

An analogue clock is
set right at 5 AM
The clock gains
20 seconds
in
3 minutes,
on
the
same day, what is
the true time when
the
clock
reads
5 PM​

Answer 1

Answer:

3:48 PM

Step-by-step explanation:

SINCE in true 3 minutes the clock moves apparently

$3 \frac{1}{3}$

minutes

here 1/3 is added due to the gain of 20 seconds in 3 minutes

now if we know that the difference between 5AM and 5 PM is 12 Hours or 12*60 minutes

now if we assume that one move of clock is of 3 1/3 minutes

then total no of moves to reach 5 PM

$\frac{12 \times 60}{3 \frac{1}{3} }$

if we solve this we get total no of moves = 216

we look into the question

3 1/3 minutes is really 3 minutes only

now for actual time every move is of 3 minutes only

then total time covered in 216 moves

$= 216 \times 3 \: minutes\\ = 648 \: minutes \\ = 648 \div 60 \: hours \\ = 10 \frac{4}{5 } \: hours \\ now \: in \: \frac{4}{5} \: hours \: there \: are \: 48 \: minutes$

that means the actual time is

5+10.8

15.8

3 : 48 PM

Answer 2

Given :  An analogue clock is set right at 5 AM The clock gains 20 seconds in 3 minutes,  

To Find : on the same day, what is the true time when the clock reads 5 PM.

Solution:

An analogue clock is set right at 5 AM

The clock gains 20 seconds in 3 minutes

=> Clock shows time 3 minutes 20 secs  when time actual has been 3 minutes

Clock shows 3 minutes 20 secs = 3 * 60 + 20  = 200 Sec

While actual time = 3 minutes = 180 sec

Every 200 Secs  of clock time actual time = 180 sec

For every  1 sec of clock time  actual time = 180/200  =  9/10 Sec

Hence actual time is  ( 9/10) of clock time

Clock reads 5PM after clock 12 hrs

Hence actual time had been  = (9/10) 12   hrs

or time left for 5PM  =  (1/10) 12  hrs  

= 1.2 hrs = 1 hr  12   minutes

so actual times  1 hr  12   minutes  before 5 PM =   12 minutes before 4 PM

= 3 hr 48  Minutes  PM

true time when the clock reads 5 PM.  =  3 hr 48  Minutes   PM

3 : 48 PM

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