Question

An analysis of organic compound gave 74% of c 8.65%of h 17.3% n what is empirical firmula

Answer 1

for c= 74/12= 6.1

for h  8.6/1= 8.6

hor n =17.3/14=1.2

now divide three values by minimum value

c= 6.1/1.2=5

h=8.6/1.2=7

n=1.2/1.2=1

answer=c5h7n