Question

An analysis of pyrex glass showed 12.9% B2O3 2.2% AL2O3 3.8% NA2O 0.4% K2O AND REMAINING SIO2 what is the ratio of Si to B atoms in the glass​

Answer 1

Answer:

Explanation:

As we know that, B2O3 is present at 12.9% , Al2O3 is present at 2.2% , Na2O is present at 3.8% and K2O is present at 0.4% . This means that SiO2 will be present at 100−(12.9+2.2+3.8+0.4) = 80.7% . Now, if we assume the weight of the glass compound to be 100g, this means that the weight of SiO2 will be 80.7 g and the weight of B2O3 will be 12.9 g.

Now, we shall convert them into the number of moles present:

moles of B2O3 = 12.970 = 0.184

As there are 2 atoms of boron in each molecule of B2O3 . This means that the number of moles of boron is twice the number of moles of B2O3. So:

moles of Boron = 0.184×2 = 0.368

For SiO2 :

moles of SiO2 = 80.760=1.34

So, the moles of silicon will be 1.34 moles .

Now, we know that the number of moles of an element will be proportional to the number of atoms present. Thus, the ratio of silicon atoms to boron atom will be:

⇒number of Silicon atoms number of Boron atoms=1.3450.368

The ratio of the atoms of silicon to the atoms of boron will be 1.3450.368 .