An ancient coin made of pure gold weighs 11.58g. Find its
volume when the density of gold is 19,300 kg/m^3.
Answers
Answered by
1
Answer:
VOLUME OF COIN IS 0.6cm3
Step-by-step explanation:
EXPLANATION
Weight of the coin =11.58g
Density of gold =19300kg/m3
TO FIND
Volume of the coin
Firstly, let's convert the unit of density of gold from kg/m3 to g/cm3
1kg/m3 =19300(0.001)
19.3g/cm3
Volume =Weight /Density
Substituting values, we get :
Volume =11.58/19.3
Volume = 0.6cm3
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Answered by
1
★ Given :
» An ancient crown made of pure gold weighs 11.58g.
» density of gold is 19,300 kg/m³
★ Need To FinD :
➟ Volume of gold in crown?
★ Formula Used Here :
➣ Volume = Weight / Density
❒ Conversion Needed :
⪼ 19300kg/m³ into g/m³
⪼ 19300 × 0.001
⪼ 19.3g/m³
⌬ According to Question :
➮ Volume = Weight / Density
➮ Volume = 11.58 / 19.3g/m³
➮ Volume = 0.6cm3
✠ Therefore :
➪ The Volume of pure gold in Crown is 0.6cm³
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