Math, asked by kaurkhushmeet17, 2 months ago

An ancient coin made of pure gold weighs 11.58g. Find its
volume when the density of gold is 19,300 kg/m^3.​

Answers

Answered by dipukgp2013
1

Answer:

VOLUME OF COIN IS 0.6cm3

Step-by-step explanation:

EXPLANATION

Weight of the coin =11.58g

Density of gold =19300kg/m3

TO FIND

Volume of the coin

Firstly, let's convert the unit of density of gold from kg/m3 to g/cm3

1kg/m3 =19300(0.001)

19.3g/cm3

Volume =Weight /Density

Substituting values, we get :

Volume =11.58/19.3

Volume = 0.6cm3

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Answered by SANDHIVA1974
1

★ Given :

» An ancient crown made of pure gold weighs 11.58g.

» density of gold is 19,300 kg/m³

★ Need To FinD :

➟ Volume of gold in crown?

★ Formula Used Here :

➣ Volume = Weight / Density

❒ Conversion Needed :

⪼ 19300kg/m³ into g/m³

⪼ 19300 × 0.001

⪼ 19.3g/m³

⌬ According to Question :

➮ Volume = Weight / Density

➮ Volume = 11.58 / 19.3g/m³

➮ Volume = 0.6cm3

✠ Therefore :

➪ The Volume of pure gold in Crown is 0.6cm³

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