Question

an angel is 3/5 of its complement. What is its magnitude​

Answer 1

Answer:

let the complement be x so

ATQ,

x + (4x)/5 = 90°

9x/ 5 = 90°

x = (90° ×5)/9 = 50°

so angles are 50° and 40°

Answer 2

Answer:

x= 4/5(90-x)

x= 72-4x/5

x+4x/5 = 72

5x = 360

x= 72