An angiospermic plant has to produce 88 viable ovules. How many meiotic division will be needed to produce equal numbers of female gametophyte by this plant. a- 88 b- 22 c- 44 d-132
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Answered by
17
The statement that will be followed is, “An angiospermic plant has to produce 88 viable ovules. There will be 88 meiotic division will be needed to produce equal numbers of female gametophyte by this plant.”
One division will give you the value of the 4 ovules that can degenerate three. Also, the functional will be the same in regards to the chalazal ovule.
Answered by
6
Option 'a' is the right answer
Explanation:
- Ovule contains the female gametophyte or the embryo sac. Each ovule usually contains only one embryo sac .
- Each embryo sac is formed by meiotic division of the diploid mother cell
- The end result of a meiotic division is 4 haploid cells, in most cases, of the 4 haploid cells formed, three degenerate and one develops into the embryo sac .
- Therefore, to produce 88 viable embryo sacs 88 meiotic divisions are required So, the correct answer is '88'.
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