An angle between vectors p and r has a measure of 120°. If p = 8 and [F] = 8, calculate p(p-r).
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from the given information we have a data as follows
an angle beetween vector p and r is measure of 120 .the p and r magnitude is also 8
asked to compute the value of p(p‐r)
consider given equation
p× p(p‐r)
=(p×p)‐(p×r)
=0‐(p×r)
= ‐|p| . |r| .sin deta
= p= 8 and r =8
= ‐(8×8×sin 120 degree)
= ‐64 × root 3/2
‐64 divided by 2 is ‐32
= ‐32 × root 3
= ‐32root 3
therefore the value of p(p‐r) is ‐32root 3
I hope this is help for you
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Answer:
Step-by-step explanation:
p . (p - q) = p^2 - p . q = p^2 - p q Cos [alpha] = 64 - 64 Cos [120 deg] =
64 (1 - Cos [120 deg]) = 2 * 64 Sin^2 [60] deg = 2 * 64 (Sqrt [3] / 2)^2 = 96
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