An angle bisector OX of ZAOB is drawn. A
point P on OX is joined to M and N on OB
and OA in such a way that OM=ON. Show
that AOPM SAOPN by SAS congruence condition :
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Let M and N be the mid point of OA and OB. Let us join PM and PN. PM and PN are bisectors of OA and OB respectively
In AOMP and AONP, angle MOP = angle UP[ because OP is
bisector)
side OP is common to both triangles.
side OM = ON (we assumed)
hence AOMP and AONP are congruent. hence side PM = side PN
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