An angle exceeds 3 times its supplement by 40degree.find the angle
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Let one angle be 3x+40
and another angle be x
3x+40+x = 180
4x+40 = 180
4x = 180-140
4x = 140
x = 140÷40
x = 35
One angle = 3x+40 = 3×35+40
= 105+40 = 145degree
another angle = x = 35degree
and another angle be x
3x+40+x = 180
4x+40 = 180
4x = 180-140
4x = 140
x = 140÷40
x = 35
One angle = 3x+40 = 3×35+40
= 105+40 = 145degree
another angle = x = 35degree
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