an angle inscribed in a semicircle is a right angle triangle,prove by vector method.
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An angle inscribed in a semicircle is a right angle triangle,prove by vector method.
Àñßwër ❤️:⤵️
Let AB be diameter and O be the centre of a circle.
Let P be a point on the semi-circle.
Join PA,PB & PO.
By the law of triangle of vectors
vector PA= vector PO+ vector OA
vector PB= vector PO+vector OB= vector PO - vector OA
Since vector OB = vector OA
Consider,
vector(PA⋅PB)=vector(PO+OA)⋅vector(PO−OA)
=vector ∣ PO ∣ 2 −vector ∣ OAb∣ 2
Since,vector∣PO∣=vector∣OA∣=radiusthecircle.
=0
ThereforevectorPAperpendiculartovectorPB
Therefore,∠APB=90∘
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