an angle is 1 by 5 of supplement what is its magnitude
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Let x represent the unknown angle
It supplement will be 180-x
Since the unknown angle is 1/5 of its supplement , you can write :
x=(1/5)(180-x)
Multiplying both sides by 5
5x=180-x
Adding x to both sides
5x+x=180-x+(-x)
6x=180
x=180/6
x=30
Hence , the magnitude of the angle is
It supplement will be 180-x
Since the unknown angle is 1/5 of its supplement , you can write :
x=(1/5)(180-x)
Multiplying both sides by 5
5x=180-x
Adding x to both sides
5x+x=180-x+(-x)
6x=180
x=180/6
x=30
Hence , the magnitude of the angle is
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