Question

An angle is 10 degree more than its complement. What it is measure

Answer 1

Let 1st angle be x
So, another angle. x+10

x+x+10=90
2x=90-10
x=80/2
=40
1st angle =x=40°
2nd angle=x+10=40+10=50

Answer 2

Answer:

$Required \: angle =50\degree$

Step-by-step explanation:

$Let \: x ,\: (90-x)\: are \: two\: complementary\:angles$

According to the problem given,

$x= (90-x)+10$

$\implies x=90-x+10$

$\implies x=100-x$

$\implies x+x=100$

$\implies 2x=100$

$\implies x = \frac{100}{2}$

$\implies x =50$

Therefore,

$Required \: angle = x =50\degree$

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