An angle is 18 less than its complementary angle the measure of this angle is
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Let the angles are x and 18° less than x° . So angles are x and ( x - 18 )°
Complimentary angles are the two angles whose sum is 90°.
As x and ( x - 18 ) are complementary angles, their sum will be 90°
x + ( x - 18 ) = 90
x + x - 18 = 90
2x - 18 = 90
x - 9 = 45
x = 54
Hence,
angles are :
x = 54°
x - 18 = 54 - 18 = 36°
Hence, 54° and 36° are the required complementary angles.
Complimentary angles are the two angles whose sum is 90°.
As x and ( x - 18 ) are complementary angles, their sum will be 90°
x + ( x - 18 ) = 90
x + x - 18 = 90
2x - 18 = 90
x - 9 = 45
x = 54
Hence,
angles are :
x = 54°
x - 18 = 54 - 18 = 36°
Hence, 54° and 36° are the required complementary angles.
BloomingBud:
no problem :-)
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6
: (Two) Angles whose sum is 90°
Given : An angle is 18 less than its complementary angle.
Let, the one angle be x degree
So,
the other angle is (x - 18) degree
=> x + (x - 18) = 90°
=> 2x - 18 = 90°
=> 2x = 90 + 18
=> 2x = 108
=> x = 108/2
=> x = 54
Therefore, one angle is 54°
Other angle is (x - 18) = 54 - 18 = 36°
Hence, two complementary angles are 54° and 36°.
Given : An angle is 18 less than its complementary angle.
Let, the one angle be x degree
So,
the other angle is (x - 18) degree
=> x + (x - 18) = 90°
=> 2x - 18 = 90°
=> 2x = 90 + 18
=> 2x = 108
=> x = 108/2
=> x = 54
Therefore, one angle is 54°
Other angle is (x - 18) = 54 - 18 = 36°
Hence, two complementary angles are 54° and 36°.
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