An angle is 2by3 of its complement then the angle is _and it's complement is
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If an angle is 2/3 times its complement, what is it's magnitude?
Equations::
x = (2/3)(90-x)
-----
x = 60-(2/3)x
(5/3)x = 60
x = 180/5
x = 36 degrees
If an angle is 2/3 times its complement, what is it's magnitude?
Equations::
x = (2/3)(90-x)
-----
x = 60-(2/3)x
(5/3)x = 60
x = 180/5
x = 36 degrees
Answered by
0
let the complement angle be x.
so , required angle is 2x/3.
x+2x/3 = 90°
5x/3=90°
x=90*3/5
x=54°
other angle=2*54/3
=36
so , required angle is 2x/3.
x+2x/3 = 90°
5x/3=90°
x=90*3/5
x=54°
other angle=2*54/3
=36
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