An angle is 300 more than half of its complement. find the angle in degrees.
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let the complement be x
so the unknown angle=x/2+30
from the above=x+x/2+30=90(sum of complementary angles is 90 degree)
2x/2 +x/2+30=90
3x/2=90-30
3x=60*2
x=120/3
x=40 degree
therefore, complement= 40
another unknwn angle=x/2+30=40/2+30
=20+30=50degree
so the unknown angle=x/2+30
from the above=x+x/2+30=90(sum of complementary angles is 90 degree)
2x/2 +x/2+30=90
3x/2=90-30
3x=60*2
x=120/3
x=40 degree
therefore, complement= 40
another unknwn angle=x/2+30=40/2+30
=20+30=50degree
Anonymous:
Hey in given ques increasing quantity is given 300. But u put 30
Answered by
1
Hy
Let angle be x
A/c to ques
x= 300+ (90-x)/2
2x=600 + 90-x
3x=690
x=230 ans!
Let angle be x
A/c to ques
x= 300+ (90-x)/2
2x=600 + 90-x
3x=690
x=230 ans!
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