an angle is 30degree more than one-half of its complement . find the angles in degrees
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let that one angle be ' x '
since , we know that
sum of complementary angles = 90°
so now , complementary angle of x
= 90 - x
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according to question ,
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x = 1 / 2 ( 90° - x ) + 30°
x = ( 90° - x + 30 × 2 ) / 2
2x = 90° - x + 60°
2x + x = 150
3x = 150 => x = 50°
one angle x = 50°
and its complementary angle
= 90 - x =90 - 50 = 40°
therefore , required angles are 50° , 40°
_______________________________
Your Answer : 50° , 40°
_______________________________
since , we know that
sum of complementary angles = 90°
so now , complementary angle of x
= 90 - x
_______________________________
according to question ,
_______________________________
x = 1 / 2 ( 90° - x ) + 30°
x = ( 90° - x + 30 × 2 ) / 2
2x = 90° - x + 60°
2x + x = 150
3x = 150 => x = 50°
one angle x = 50°
and its complementary angle
= 90 - x =90 - 50 = 40°
therefore , required angles are 50° , 40°
_______________________________
Your Answer : 50° , 40°
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