Question

An angle is 50%

less than by



of its supplement. Find the angle.​

Answer 1

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Let the angles be

Let the angles be ˆ

Let the angles be ˆA

Let the angles be ˆA=

Let the angles be ˆA=50

Let the angles be ˆA=50∘

Let the angles be ˆA=50∘,

Let the angles be ˆA=50∘,ˆ

Let the angles be ˆA=50∘,ˆB

Let the angles be ˆA=50∘,ˆB

Let the angles be ˆA=50∘,ˆB ˆ

Let the angles be ˆA=50∘,ˆB ˆA

Let the angles be ˆA=50∘,ˆB ˆA+

Let the angles be ˆA=50∘,ˆB ˆA+ˆ

Let the angles be ˆA=50∘,ˆB ˆA+ˆB

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆ

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆ

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆ

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are 50

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are 50∘

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are 50∘,

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are 50∘,130

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are 50∘,130∘

Let the angles be ˆA=50∘,ˆB ˆA+ˆB=180∘ ˆB=180−ˆA ˆB=180−50=130∘ The two supplementary angles are 50∘,130∘

Answer 2

Answer:

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