an angle is ten less than its complement
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0
Let one angle be A, the other is 90-A.
Now, A-(90-A)=10, therefore A=50.
Thus, the angles are 50 degrees and 40 degrees respectively.
Now, A-(90-A)=10, therefore A=50.
Thus, the angles are 50 degrees and 40 degrees respectively.
Answered by
1
Hi ,
Let x and ( 90 - x ) are
Complementary angles
According to the problem given ,
x = 90 - x -10
x + x = 80
2x = 80
x = 80/2
x = 40
One angle = x = 40°
Second angle = 90 - x
= 90 - 40
= 50°
I hope this helps you.
:)
Let x and ( 90 - x ) are
Complementary angles
According to the problem given ,
x = 90 - x -10
x + x = 80
2x = 80
x = 80/2
x = 40
One angle = x = 40°
Second angle = 90 - x
= 90 - 40
= 50°
I hope this helps you.
:)
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