an angle is twice less than thrice its compliment. find the angle
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Answer:
If their sum is 90 deg. 4y = 92 and so y = 23 deg and x = 90–23 = 67 deg. Check: 23x3–2 = 69–2 = 67.
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Let required angle = y
It’s compliment angle= 90-y
Twice of an angle = 2y
Thrice its compliment = 3(90-y)
Given that
Y=3(90-y)-2y
Y=270-3y-2y
6y=270
Y=45
Check
45=3(45)-2(45)=135-90=45
Required angle= 45
It’s compliment angle= 90-y
Twice of an angle = 2y
Thrice its compliment = 3(90-y)
Given that
Y=3(90-y)-2y
Y=270-3y-2y
6y=270
Y=45
Check
45=3(45)-2(45)=135-90=45
Required angle= 45
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