an angle is two third of its complement. find the angle
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let the angle be 2/3 x
and other angle be x
ATQ. 2/3x +X=90(COMPLEMENTARY ANGLES)
FROM HERE VALUE OF X WILL BE 54
and the angle required is 2×54÷3=36
and other angle be x
ATQ. 2/3x +X=90(COMPLEMENTARY ANGLES)
FROM HERE VALUE OF X WILL BE 54
and the angle required is 2×54÷3=36
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